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Q.

If tanθtanπ3+θtanπ3+θ=ktan3θ, then the value of k, is 

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a

1/3

b

3

c

1

d

-1

answer is D.

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Detailed Solution

We have,

  tanθtanπ3+θtanπ3+θ=ktan3θ

 tanθtanθ+313tanθtanθ31+3tanθ=ktan3θ tan3θ3tanθ13tan2θ=ktan3θ tan3θ=ktan3θk=1

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