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Q.

 If the system of linear equations x+ky+3z=0, 3x+ky-2z=0,  2x+4y-3z=0 has a non-zero solution (x, y, z) then xzy2 is equal to

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a

10

b

-30

c

30

d

-10

answer is A.

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Detailed Solution

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For non-zero solution, Δ=0

We get k = 11

On 21:2x=5zx=5z2

from 1:z=2yy=z2

xzy2=10

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