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If $V_{0}$ is the volume of a given mass of gas at 273 Kat constant pressure, then according to Charles law the volume at 10° C will be :

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$10 V_{0}$

$\frac{2}{273} (V_{0} + 10)$

$V_{0} + \frac{10}{273}$

$\frac{283}{273} V_{0}$

answer is D.

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Detailed Solution

If $V_{0}$ is the volume of a given mass of gas at 273 K at constant pressure, then according to Charles law the volume at 10° C will be : $\frac{283}{273} V_{0}$ because of $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

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