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Q.

If v1 is the frequency of the series limit of Lyman series, v2 is the frequency of the first line of Lyman series and v3 is the frequency of the series limit of the Balmer series, then:

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a

1v1=1v2+1v3

b

v1=v2-v3

c

v1-v2=v3

d

1v2=1v1+1v3

answer is A.

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Detailed Solution

For Lyman series, vL=Rc112-1n2

where n=2,3,4,.......

For the series limit of Lyman series, n=

    v1=Rc112-12=Rc                 .....(i)

For the first line of Lyman series, n=2

    v2=Rc112-122=34Rc                 .....(ii)

For Balmer series 

    vB=Rc122-1n2

where n= 3,4,5,....

For the series limit of Balmer series, n=

    v3=Rc122-12=Rc 4                .....(iii)

From equations (i), (ii) and (iii), we get

v1=v2+v3     or,   v1-v2=v3

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