If x=-5+i32 then x2+5x2+xx+5=

x=-5+i32⇒x+5=5+i32xx+5=-5+i325+i32=-3-254=-7x2+5x2+xx+5=49-7=42

If x=-5+i32 then x2+5x2+xx+5=

x=-5+i32⇒x+5=5+i32xx+5=-5+i325+i32=-3-254=-7x2+5x2+xx+5=49-7=42

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If $x = \frac{- 5 + i \sqrt{3}}{2}$ then ${(x^{2} + 5 x)}^{2} + x (x + 5) =$

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$x = \frac{- 5 + i \sqrt{3}}{2} \Rightarrow x + 5 = \frac{5 + i \sqrt{3}}{2}$

$x (x + 5) = (\frac{- 5 + i \sqrt{3}}{2}) (\frac{5 + i \sqrt{3}}{2}) = \frac{- 3 - 25}{4} = - 7$

${(x^{2} + 5 x)}^{2} + x (x + 5) = 49 - 7 = 42$

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If $x = \frac{- 5 + i \sqrt{3}}{2}$ then ${(x^{2} + 5 x)}^{2} + x (x + 5) =$