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Q.

If |x|<1, then the coefficient of xn in expansion of 1+x+x2+x3+2 is

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a

n-1

b

n

c

n+2

d

n+1

answer is D.

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Detailed Solution

1+x+x2+x3+2=1-x-12=(1x)2, (1x)2=1+2x+3x2+4x3+....+(r+1)xr+.......  coefficient of xn=n+1

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