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Q.

If x=1 and x=2 are extreme points of  f(x)=αlog|x|+βx2+x, then

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a

α=6,β=12

b

α=6,β=12

c

α=2,β=12

d

α=2,β=12

answer is C.

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Detailed Solution

f(x)=αlog|x|+βx2+x
f'(x)=α1x+2βx+1 f'(-1)=0-α-2β+1=0 f'(2)=0α+8β+2=0 β=-12, α=2

f(1)=0,f(2)=0

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