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If $\frac{x}{(1 + x^{2}) (3 - 2 x)} = \frac{A}{3 - 2 x} + \frac{Bx + C}{1 + x^{2}}$ then C =

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$\frac{- 1}{13}$

$\frac{2}{13}$

- $\frac{2}{13}$

$\frac{1}{13}$

answer is C.

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Detailed Solution

$\begin{array}{l} x = A (1 + x^{2}) + (Bx + C) (3 - 2 x); A = 2 B \\ 3 B = 2 C + 1; A = - 3 C \end{array}$

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