Q.

If (x1,y1) and (x2,y2) are ends of focal chord of  y2=4ax then x1x2+y1y2=

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a

5a2

b

a2

c

5a2

d

3a2

answer is B.

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Detailed Solution

Take (x1,y1)=(at12,2at1);(x2,y2)=(at22,2at2)

Since focal chord t1t2=1

Consider x1x2+y1y2=a2t12t22+4a2t1t2

=a2(t1t2)2+4a2t1t2

=a2(1)2+4a2(1)

=a24a2 =3a2

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