If x2−2(4λ−1)x+15λ2−2λ−7>0,(x∈R then the value of λ

Clearly, D < 04(4λ−1)2−415λ2−2λ−7<0λ2−6λ+18<0(λ−2)(λ−4)<02<λ<4

If x2−2(4λ−1)x+15λ2−2λ−7>0,(x∈R then the value of λ

Clearly, D < 04(4λ−1)2−415λ2−2λ−7<0λ2−6λ+18<0(λ−2)(λ−4)<02<λ<4

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If $x^{2} - 2 (4 λ - 1) x + (15 λ^{2} - 2 λ - 7) > 0, (x \in R$ then the value of $λ$

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2< $λ$ <8

8< $λ$ <4

-4< $λ$ <4

2< $λ$ <4

answer is D.

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Clearly, D < 0

$\begin{array}{l} 4 (4 λ - 1)^{2} - 4 (15 λ^{2} - 2 λ - 7) < 0 \\ λ^{2} - 6 λ + 18 < 0 \\ (λ - 2) (λ - 4) < 0 \\ 2 < λ < 4 \end{array}$

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If x2−2(4λ−1)x+15λ2−2λ−7>0,(x∈R then the value of λ

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If $x^{2} - 2 (4 λ - 1) x + (15 λ^{2} - 2 λ - 7) > 0, (x \in R$ then the value of $λ$