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Q.

If x2+x+1=0. then the value of

x+1x+x2+1x2++x52+1x52 equals

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a

1

b

–1

c

0

d

–52

answer is D.

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Detailed Solution

Ifx2+x+1=0thenx=ω,ω2(x+1x)+(x2+1x2)++(x52+1x52)=(ω+1ω)+(ω2+1ω2)++(ω52+1ω52)=(ω+ω2)+(ω2+w)++(ω+ω2)=(1)+(1)++(1)(52times)=52

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If x2+x+1=0. then the value ofx+1x+x2+1x2+……+x52+1x52 equals