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Q.

If x2+x+1=0, then the value of x+1x2+x2+1x22+.....+x27+1x272 is

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a

27

b

72

c

45

d

54

answer is D.

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Detailed Solution

x2+x+1=0    x=w or w2  x+1x2+x2+1x22+....+x2+1272 = w+1w+w2+1w22+....w27+1w272w=w4=w7=....=w25w2=w5=w8=....=w26w3=w6=w9=....w24=w27

 Given expression 

 =9 w+1w2+w2+1w22+w3+1w32 =9w+w22+w2+w+1+12 =9-12+-12+22 =91+1+4 =54

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