Ifx=54, y=2, z=43 then

x=54, y=2, z=43Equating the order⇒534×3, 262×6, 443×4⇒ 12512,6412, 25612∴z>x>y

Ifx=54, y=2, z=43 then

x=54, y=2, z=43Equating the order⇒534×3, 262×6, 443×4⇒ 12512,6412, 25612∴z>x>y

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If $x = \sqrt[4]{5}, y = \sqrt{2}, z = \sqrt[3]{4}$ then

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$x > y > z$

$x < y < z$

$z > x > y$

$y > z > x$

answer is C.

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$x = \sqrt[4]{5}, y = \sqrt{2}, z = \sqrt[3]{4}$

Equating the order

$\Rightarrow \sqrt[4 \times 3]{5^{3}}, \sqrt[2 \times 6]{2^{6}}, \sqrt[3 \times 4]{4^{4}}$

$\Rightarrow \sqrt[12]{125}, \sqrt[12]{64}, \sqrt[12]{256}$

$∴ z > x > y$

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Ifx=54, y=2, z=43 then

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If $x = \sqrt[4]{5}, y = \sqrt{2}, z = \sqrt[3]{4}$ then