If ${\text{⨍ (x)=5x}}^3{\text{+4x}}^2\text{-13x-25}$ and ${\text{⨍ (x-3)=5x}}^3{\text{-41x}}^2\text{+98x+k}$ then $\mathrm{k}=$

$\begin{array}{l}Iff\left(x\right)=5x^3+4x^2-13x-25--\left(1\right)\\ f(x-3)=5x^3-41x^2+98x+k--\left(2\right)\\ putx=0in\left(2\right)\Rightarrow f(-3)=k\\ putx=-3in\left(1\right)\\ k=5{(-3)}^3+4{(-3)}^2-13(-3)-25\\ =-135+36+39-25\\ =-85\end{array}$