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Q.

If x6+1=0, then x=

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a

cis2k+1π6, k=0,1,2,3,4,5

b

cis2k-1π6, k=0,1,2,3,4,5

c

cis3k+1π6, k=0,1,2,3,4,5

d

cis3k-1π6, k=0,1,2,3,4,5

answer is A.

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Detailed Solution

x6+1=0x6=-1x6=cos π+i sin πx=cos π+i sin π16x=cos 2+π6+i sin 2+π6, k=0, 1. 2, 3, 4, 5x=cis (2k+1)π6 : k=0, 1, 2, 3, 4, 5.

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If x6+1=0, then x=