Q.

If x=a+b, y=+2, z=2+ then which of the following is true

I   : x+y+z0       II  : x2+y2+z2=6ab

III   : x3+y3+z3=3(a3+b3)

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a

only I, II 

b

only II, III

c

only I, III 

d

all are true

answer is B.

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Detailed Solution

x=a+b,  y=aw+bw2,  z=aw2+bw

x+y+z=a(1+w+w2)+b(1+w2+w)=0

x2+y2+z2=(a+b)2+(aw+bw2)2+(aw2+bw)2 

 =a2+b2+2ab+a2w2+b2w4+2abw3+a2w4+b2w2+2abw3 =a2(1+w2+w4)+b2(1+w4+w2)+6ab =6abx+y+z=0  x3+y3+z3=3xyz =3(a+b) (aw+bw2) (aw2+bw) =3(a+b) (a2w3+b2w3+ab(w2+w4)) =3(a+b) (a2-ab+b2) =3(a3+b3)

only II, III are true.

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