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$If x = \cos 10^{0} - \sin 10^{0} then$

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$x \geq 0$

$x < 0$

$x > 0$

$x = 0$

answer is A.

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Detailed Solution

$\begin{array}{l} x = \cos 10^{0} - \sin 10^{0} \\ For x < 45^{0} \\ \cos x > \sin x \\ \cos x - \sin x > 0 \\ \forall x \in (0, π / 4) \end{array}$

$P u t x = 10^{0} \begin{array}{l} ∴ \cos 10^{0} - \sin 10^{0} > 0 \\ ∴ x > 0 \end{array}$

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