If x+iy=i−i123i1−12i then

x+iy=i−i123i1−12i =i[−3−2]+i[2i+1]+i[4+3i] =−5i−2+i+4+3ix+iy=2−i

If x+iy=i−i123i1−12i then

x+iy=i−i123i1−12i =i[−3−2]+i[2i+1]+i[4+3i] =−5i−2+i+4+3ix+iy=2−i

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If $x + i y = |\begin{matrix} i & - i & 1 \\ 2 & 3 i & 1 \\ - 1 & 2 & i \end{matrix}|$ then

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$x = - 2, y = 3$

$x = 1, y = 2$

$x = 2, y = - 1$

$x = 2, y = 3$

answer is B.

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Detailed Solution

$x + i y = |\begin{matrix} i & - i & 1 \\ 2 & 3 i & 1 \\ - 1 & 2 & i \end{matrix}| = i [- 3 - 2] + i [2 i + 1] + i [4 + 3 i]$

= $- 5 i - 2 + i + 4 + 3 i$

$x + i y = 2 - i$

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If x+iy=i−i123i1−12i then

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If $x + i y = |\begin{matrix} i & - i & 1 \\ 2 & 3 i & 1 \\ - 1 & 2 & i \end{matrix}|$ then