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If $⨍ (x)=logx, x=2, δx=0.02,$ then $df =$

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log (1.01)

0.01

–log (1.01)

–0.01

answer is B.

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Detailed Solution

$df = f^{1} (x) σx = \frac{1}{x} . δ x = \frac{0.02}{2} = 0.01$

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