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Q.

If x=rcosαcosβcosγ,y=rcosαcosβsinγ,z=rsinαcosβ,  and μ=rsinβ, then  x2+y2+z2+μ2=

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a

r2

b

1

c

r

d

0

answer is D.

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Detailed Solution

x=rcosαcosβcosγ

y=rcosαcosβsinγ

z=rsinαcosβ

u=rsinβ

x2+y2+z2+μ2

=r2cos2αcos2βcos2γ+r2cos2αcos2βsin2γ+r2sin2αcos2β+r2sin2β

=r2cos2αcos2β(cos2γ+sin2γ)+r2sin2αcos2β+r2sin2β

=r2cos2αcos2β+r2sin2αcos2β+r2sin2β

=r2cos2β(cos2α+sin2α)+r2sin2β

=r2cos2β+r2sin2β

=r2(1)=r2

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