If ${\text{⨍ (x)=x}}^4{\text{+3x}}^2\text{-6x-2}$ then the coefficient of ${\mathrm{x}}^3$ in $\text{⨍ (x+1)}$ is

$\begin{array}{l}f\left(x\right)=x^4+3x^2-6x-2\\ f(x+1)={(x+1)}^4+3{(x+1)}^2-6(x+1)-2\\ ={(x^2+1+2x)}^2+3(x^2+1+2x)-6x-6-2\\ =x^4+1+4x^2+2x^2+4x+4x^3+3x^2+3+6x-6x-8\\ =x^4+4x^3+9x^2+4x-4\\ x^{3}co.effis4\end{array}$