If ⨍ x=x cos1x+9x2, x≠0 k , x≠0then f is continuous if the value of 'k' is

fx=xcos 1x+9x2; x≠0k; x=0 is continuous⇒k=f0=limx→0 xcos 1x+9x2=0finite value+9(0)k=0Option (3) correct

If ⨍ x=x cos1x+9x2, x≠0 k , x≠0then f is continuous if the value of 'k' is

fx=xcos 1x+9x2; x≠0k; x=0 is continuous⇒k=f0=limx→0 xcos 1x+9x2=0finite value+9(0)k=0Option (3) correct

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If $⨍ (x) = \{\begin{cases} |x| cos (\frac{1}{x}) {+9x}^{2}, x≠0 \\ k, x \neq0 \end{cases}$ then $f$ is continuous if the value of $' k'$ is

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$f (x) = \{\begin{matrix} |x| \cos \frac{1}{x} + 9 x^{2}; x \neq 0 \\ k; x = 0 \end{matrix}$ is continuous

$\Rightarrow k = f (0) = \lim_{x \to 0} |x| \cos \frac{1}{x} + 9 x^{2}$

$= 0 (finite value) + 9 (0)$

$k = 0$

Option (3) correct

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If ⨍ x=x cos1x+9x2, x≠0 k , x≠0then f is continuous if the value of 'k' is

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If $⨍ (x) = \{\begin{cases} |x| cos (\frac{1}{x}) {+9x}^{2}, x≠0 \\ k, x \neq0 \end{cases}$ then $f$ is continuous if the value of $' k'$ is