If y=2+|x|−|x−1|−|x+1|, then y′,−12+y′12+y′32+y′52=

fx=x+2x 1 y′,−12+y′12+y′32+y′52=-1+1-1-1=-2

If y=2+|x|−|x−1|−|x+1|, then y′,−12+y′12+y′32+y′52=

fx=x+2x 1 y′,−12+y′12+y′32+y′52=-1+1-1-1=-2

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If $y = 2 + | x | - | x - 1 | - | x + 1 |, then y^{'}, (- \frac{1}{2}) + y^{'} (\frac{1}{2}) + y^{'} (\frac{3}{2}) + y^{'} (\frac{5}{2}) =$

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$f (x) = \{\begin{cases} x + 2 & x < - 1 \\ - x & - 1 < x \leq 0 \\ x & 0 < x \leq 1 \\ 2 - x & x > 1 \end{cases}$

$y^{'}, (- \frac{1}{2}) + y^{'} (\frac{1}{2}) + y^{'} (\frac{3}{2}) + y^{'} (\frac{5}{2}) = - 1 + 1 - 1 - 1 = - 2$

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If y=2+|x|−|x−1|−|x+1|, then y′,−12+y′12+y′32+y′52=

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If $y = 2 + | x | - | x - 1 | - | x + 1 |, then y^{'}, (- \frac{1}{2}) + y^{'} (\frac{1}{2}) + y^{'} (\frac{3}{2}) + y^{'} (\frac{5}{2}) =$