$\mathrm{If} \mathrm{y}={\sin }^2{\mathrm{x}}^0 \mathrm{then} \frac{\mathrm{dy}}{\mathrm{dx}}=$

$$\begin{gathered} \mathrm{y}={\sin }^2 {\mathrm{x}}^0 \\ ={\sin }^2 \frac{\mathrm{\pi } \mathrm{x}}{180} \\ \frac{\mathrm{dy}}{\mathrm{dx}}=2 \sin \frac{\mathrm{\pi } \mathrm{x}}{180}·\cos \frac{\mathrm{\pi } \mathrm{x}}{180}·\frac{\mathrm{\pi }}{180} \\ =\sin 2\frac{\mathrm{\pi } \mathrm{x}}{180}·\frac{\mathrm{\pi }}{180} \\ =\sin 2{\mathrm{x}}^0·\frac{\mathrm{\pi }}{180} \end{gathered}$$