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Q.

If y=xa+xb+xa+xb+..+ to  then dydx=

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a

1a(2y+b)

b

ba(2y+b)

c

1ab(2y+b)

d

ab(2y+b)

answer is B.

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Detailed Solution

 Here, y=xa+xb+y=x(b+y)ab+ay+x

 aby+ay2+xy=bx+xy

 aby+ay2=bx

 On differentiating w.r.t. x, we get 

abdydx+2aydydx=b

dydx=ba(b+2y)

 

 

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