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Q.

If y=xlog|cx|where c is an arbitrary constant is the general solution of the differential equation dydx=yx+ϕyx then the function ϕxy is . . . .

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a

y2x2

b

y2x2

c

x2y2

d

x2y2

answer is D.

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Detailed Solution

y=xlog|cx|log|cx|=xy;

logc+logx=xy 1x=y-xdydxy2 y2x=yxdydx;

xdydx=yy2xdydx=yxy2x2

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