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If $z -$ axis be the internuclear axis, which of the following combination of orbitals would not form $π -$ bond?

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p_{x} + p_{x}

d_{x y} + d_{x y}

d_{2 x} + d_{2 x}

d_{y z} + d_{y z}

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detailed solution

Correct option is B

$d_{x y} - d_{x y}$ form $π -$ bond if $z -$ axis is the internuclear axis.

Atomic orbitals connect in a sideways positive (same phase), perpendicular to the internuclear axis direction, to generate pi bonds.

Hence, the option B is correct.

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If z-axis be the internuclear axis, which of the following combination of orbitals would not form π-bond?

Unlock the full solution & master the concept.

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If $z -$ axis be the internuclear axis, which of the following combination of orbitals would not form $π -$ bond?