If $\mathrm{z}-$axis be the internuclear axis, which of the following combination of orbitals would not form  $\mathrm{\pi }-$bond?

$d_{xy}-d_{xy}$ form  $\mathrm{\pi }-$bond if $\mathrm{z}-$axis is the internuclear axis.

Atomic orbitals connect in a sideways positive (same phase), perpendicular to the internuclear axis direction, to generate pi bonds.

Hence, the option B is correct.