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If $z_{1} = 2 i - 3 and z_{2} = x - iy$ and $z_{2} - z_{1} = 0$ then find x, y values are

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2,3

5,6

-1,0

-3,-2

answer is D.

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Detailed Solution

$\begin{array}{l} x - iy - (2 i - 3) = 0 \\ x - iy - 2 i + 3 = 0 \\ (x + 3) + i (- y - 2) = 0 + i (0) \end{array}$
Comparing coefficients
$x + 3 = 0 x = - 3$ $- y - 2 = 0 - y = 2 y = - 2$

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