If $\mathrm{z}(1+\mathrm{a})=\mathrm{b}+\mathrm{ic}\text{ and }{\mathrm{a}}^2+{\mathrm{b}}^2+{\mathrm{c}}^2=1$ then $\frac{(1+\mathrm{iz})}{(1-\mathrm{iz})}=$

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