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Q.

If z1 and z2 are the roots of the equation z2+az+b=0, if the origin, z1 and z2 form an equilateral triangle then

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a

a2=3b

b

a2+3b=0

c

b2=3a

d

b2+3a=0

answer is A.

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Detailed Solution

z1+z2=a, z1 z2=b

Now, 0, z1, z2 form an equilateral triangle

02+z12+z22=0z1+z2+z1z2z1+z22=3z1z2a2=3b

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