Q.

I) H2O2+Cl22HCl+O2; II)H2O2+2NaOH2Na2O2+2H2O; Role of H2O2 in the above reactions is

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a

 Reducing agent in (I) and oxidizing agent in (II)       

b

 Oxidizing in (I) and acid in (II) 

c

Reducing agent in (I) and acid in  (II)     

d

 Oxidizing agent in (I) and reducing agent in (II)        

answer is C.

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Detailed Solution

 H2O2 acts as reducing agent in (I); It reduces Cl2 to Cl-

H2O2 acts as an acid in (II) ; It reacts with sodium hydroxide to form a salt sodium peroxide ;

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