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Q.

i×i×a+j×j×a+k×k×a=

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a

a

b

-a

c

2a

d

-2a

answer is C.

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Detailed Solution

  (i·a) i-a+(j·a) j-a+(k·a) j-aa=xi+yj+zkxi+yj+zk-3a=a-3a =-2a

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