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Q.

Imagine a light planet revolving around a very massive star in a circular orbit of radius R with period T. If the gravitational force of attraction between the planet and the star is proportional to R52 , thenT2 is proportional to

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a

R3

b

R12

c

R32

d

R3.5

answer is D.

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Detailed Solution

The mass of light planet = m

Radius in which it is revolving = R

Orbital velocity =v0

v0=2πRT

Gravitational force between massive star & planet

FR5/2

F=kR5/2  (k is constant)

We can have for orbiting planet

mv02R=F

mv02R=k.R5/2

v02=kmR3/2v0=2πRT

4π2R2T2=kmR3/2

R2+3/2T2=km4π2

R7/2T2=constant

i.e.,T2R7/2orT2R3.5

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