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Q.

Imagine a uniform wire of length ‘L’ suspended from the ceiling whose Young’s modulus of elasticity increases linearly from Y0 at bottom to Y0+kL  at the top. If ‘A’ is the area of cross-section and W be the load at its bottom then (neglect change in area of cross-section).

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a

Tension is maximum at the top of the rope and equal to W+λLg,whereλ  is linear density of the Rope 
 

b

The strain energy developed in the wire is W22Akln[1+kLY0]  (if mass of rope is negligible compared to W)

c

Tension is maximum at the bottom of the rope and equal to W

d

Total elongation of the wire is WAkln[1+kLY0]    (if mass of rope is negligible compared to W)

answer is A, B, C.

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Detailed Solution

Question Image

 

 

 

 

 

de=WdyA(Y0+kY)   Integratee=WAlog[Y0+kYk]0L=WAklog(1+kLY0)

Strain energy  =12Fe=12W×WAklog(1+kLY0)

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