Imagine that a reactor converts all given mass into energy and that operates at a power level of 109 watt. The mass of the fuel consumed per hour in the reactor will be (velocity of light, c = 3 x 108 m/s)

Power P= Energy time P=tt=mc2tm=p×tC2mt=1093×1082×3600 hour mt=36×109×1016=4×10−2gmh

Imagine that a reactor converts all given mass into energy and that operates at a power level of 109 watt. The mass of the fuel consumed per hour in the reactor will be (velocity of light, c = 3 x 108 m/s)

Power P= Energy time P=tt=mc2tm=p×tC2mt=1093×1082×3600 hour mt=36×109×1016=4×10−2gmh

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Imagine that a reactor converts all given mass into energy and that operates at a power level of 10⁹ watt. The mass of the fuel consumed per hour in the reactor will be
(velocity of light, c = 3 x 10⁸ m/s)

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6.6 x 10^-5 gm

0.96 gm

0.8 gm

4 x 10^-2 gm

answer is C.

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Detailed Solution

Power $P = \frac{Energy}{time}$
$\begin{array}{l} P = \frac{t}{t} = \frac{{mc}^{2}}{t} \\ m = \frac{p \times t}{C^{2}} \\ \frac{m}{t} = \frac{10^{9}}{{(3 \times 10^{8})}^{2}} \times \frac{3600}{hour} \\ \frac{m}{t} = \frac{36 \times 10}{9 \times 10^{16}} = 4 \times 10^{- 2} \frac{gm}{h} \end{array}$