$\begin{array}{l} i) M g + C l_{2} \to M g C l_{2} \\ i i) 2 F e_{2} O_{3} + 4 A l \to 4 F e + 2 A l_{2} O_{3} \\ i i i) C u S O_{4} + Z n \to C u + Z n S O_{4} \\ i v) H_{2} + S \to H_{2} S \end{array}$
The following options are given based on the above four chemical equations. Choose the incorrect set which represents substance oxidised, substance reduced, oxidising agent and reducing agent respectively.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

Mg (Substance oxidized) $C l_{2}$ (Substance reduced)

$C l_{2}$ (Oxidising agent) Mg (Reducing agent)

Zn (Substance oxidized) $C u S O_{4}$ (Substance reduced)

$C u S O_{4}$ (Oxidising agent) Zn (Reducing agent)

Al (Substance oxidized) $F e_{2} O_{3}$ (Substance reduced)

$F e_{2} O_{3}$ (Oxidising agent) Al (Reducing agent)

$H_{2}$ (Substance oxidized) S (Substance reduced)

$H_{2}$ (Oxidising agent) S (Reducing agent)

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

In the given equation $H_{2} + S \Rightarrow H_{2} S$ . is reducing agent and ‘S’ is oxidizing agent.

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE