In a transistor amplifier, when signal voltage changes by 0.01 volt, the base current changes by $10 μ A$ and collector current changes by 1 mA. If the collector resistance $R_{C} = 4 K Ω$ and load resistance $R_{L} = 8 k Ω$ , than the current gain is:

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Detailed Solution

Given that $Δ I_{B} = 10 μ A, Δ I_{C} = 1 m A$

$Δ V_{B E} = 0.01 V$

(the transistor is used I common-emitter configuration)

$R_{C} = 4 k Ω$ and $R_{L} = 8 k Ω$

Current gain $β = \frac{Δ I_{C}}{Δ I_{B}} = \frac{1 m A}{10 μ A} = 100$

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