In an amino acid, the carboxyl group ionizes at pKa 1=2.34 and ammonium ion at pKa 2=9.60. The isoelectric point of the amino acid is at pH

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In an amino acid, the carboxyl group ionizes at $p K_{a_{1}} = 2.34$ and ammonium ion at $p K_{a_{2}} = 9.60.$ The isoelectric point of the amino acid is at pH

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6.97

9.60

5.97

2.34

answer is A.

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Detailed Solution

Isoelectric point (pH)

$= \frac{p K_{a_{1}} + p K_{a_{2}}}{2} = \frac{2.34 + 9.60}{2} = 5.97$

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