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Q.

In ΔABC   if  C=3B   and  B= 2 3 [A+B]  , find the values of  A,B,C  are ____ respectively.


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Detailed Solution

The ΔABC is represented in below picture
IMG_256Let the angles in the above triangle are
CAB=α  
ABC=β  
ACB=γ  
From the given data,
ABC=β= 2 3 [CAB+ABC] β= 2 3 [α+β] β 2 3 β= 2 3 α 1 3 β= 2 3 α  
Multiplying the above equation with 3, then
β=2α α= 1 2 β.....(i)  
Now given that
ACB=3ABC γ=3β........(ii)  
Finding the sum of the angles in the triangle,
CAB+ABC+ACB=α+β+γ  
From equations (i) and (ii) substituting the values of  α,γ   in the above equation, then
CAB+ABC+ACB=α+β+γ CAB+ABC+ACB= 1 2 β+β+3β CAB+ABC+ACB= 9 2 β.......(iii)  
But we know that the sum of angles in a triangle is equal to 180 °  , so
CAB+ABC+ACB= 180 °  
From equation (iii),
9 2 β= 180 9β= 360 β= 360 9 = 40  
From equation (i) the value of  α   is,
α= 1 2 β = 1 2 ( 40 ° ) = 20 °  
From equation (ii), the value of γ  is
γ=3β γ=3( 40 ° ) γ= 120 °  
So, the angles of the triangle are
CAB=A=α A= 20 ° ABC=B=β B= 40 °  
InQuestion Image if Question Image and Question Image, find the values of Question Imageare 20°, 40° and 120° respectively.
 
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