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In $∆ P Q R, Q R = 10, R P = 11$ and $P Q = 12 . D$ is the midpoint of PR. DE is drawn parallel to P Q meeting QR in E.EF is drawn parallel to RP meeting PQ in F. What is the length of DF?

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$\frac{11}{2}$

$\frac{33}{4}$

answer is D.

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Detailed Solution

Given, $D$ is the midpoint of PR.

and $D E ∥ P Q$ .

$E$ is the midpoint of QR.

Question Image

Similarly, F is the midpoint of PQ.

Then, from Midpoint Theorem, $D E ∥ A B$ and $D F = \frac{1}{2} Q R$

Since, $Q R = 10$ .

$D F = \frac{1}{2} (10) = 5$

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