Q.

In Δ PQR, ∠R = ∠P and QR = 4 cm and PR = 5 cm. Then the length of PQ is ________.

NCERT Exemplar Solutions For Class 9 Maths Chapter 7 Exercise 7.1-4

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a

 9 cm

b

4 cm

c

7 cm

d

6 cm

answer is B.

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Detailed Solution

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Given: ΔPQR, ∠R = ∠P and QR = 4 cm and PR = 5 cm

Since, ∠R = ∠P

Δ PQR is an isosceles triangle.

Hence, PQ = QR

⇒ PQ = 4 cm

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In Δ PQR, ∠R = ∠P and QR = 4 cm and PR = 5 cm. Then the length of PQ is ________.