In pyranose of glucose oxide (ether) linkage is formed between

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$C_{1}$ and $C_{5}$

$C_{1}$ and $C_{6}$

$C_{2}$ and $C_{5}$

$C_{2}$ and $C_{6}$

answer is C.

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Detailed Solution

Pyranose ring structure of glucose is due to hemiacetal formation between C1 and C5 carbon atoms. In general, a pyranose is any cyclic isomer that has a five carbon atoms and one oxygen atom in a ring of six atoms.

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