In young's double slit experiment, $16$ fringes are observed to be formed in a certain segment if wavelength of $600 nm$ is used. If the wavelength of light is changed to $480 nm$ , number of fringes observed in the same segment

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$20$

$10$

$30$

$40$

answer is B.

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Detailed Solution

Wavelength $λ_{1} = 600 n m$

Wavelength $λ_{2} = 480 n m$

Number of fringes $n_{1} = 16$

Number of fringes $n_{2} = ?$

$n_{1} λ_{1} = n_{2} λ_{2}$

$\Rightarrow n_{2} = \frac{n_{1} λ_{1}}{λ_{2}}$

$= \frac{16 \times 600}{480}$

$∴ n_{2} = 20$

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