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In a 0.2 molal aqueous solution of a weak acid HX the degree of dissociation is 0.25. The freezing point of the solution will be nearest to: ( $K_{f} = 1.86 {Kkgmol}^{- 1}$ )

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-0.26°C

0.465°C

-0.48°C

-0.465°C

answer is D.

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Detailed Solution

$i = 1 + α \Rightarrow 1 .25 {ΔT}_{f} = K_{f} \cdot m . i \Rightarrow 1.86 \times 0.2 \times 1.25 or {ΔT}_{f} = 0.465 or T_{f} = - {0.465}^{\circ} C$

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