In a 50 m race, A can give a start of 5 m to B and a start of 14 m to C. In the same race, how much start can B give to C?

When B covers 45 m, C covers = 36 m 

when B covers 50 m, C covers

$=\frac{36}{45}\times 50 \mathrm{m}=40 \mathrm{m}$

Hence, B can give a start of (50 - 40) m i.e. 10 m to C.

$\therefore$ Option (b) is the correct answer.