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Q.

In a ΔABC  , the sides BC=5,CA=4,AB=3 . If A0,0  and the internal bisector of angle A meets the side BC in D127, 127 . Then the incenter of ΔABC  is 

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a

(2,2)

b

(3,2)

c

(2,3)

d

(1,1)

answer is D.

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Incentre I divider AD¯  in the ratio b+c:a

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