In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked randomly. The probability that it is neither red nor green is

Total balls $=8+7+6$

$=21$

E= Event that the ball drawn in neither red nor green (or)

E = Event that the balls drawn is blue

$n\left(E\right)=7$

$p\left(E\right)=\frac{n\left(E\right)}{n\left(s\right)}=\frac{7}{21}=\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$3$}\right.$