In a buffer solution containing equal concentrations of $C N^{-}$ and HCN , The $K_{a}$ for HCN is $10^{- 4} .$ The $P^{H}$ of the buffer solution is

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answer is A.

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Detailed Solution

$\begin{array}{l} K a = 10^{- 4}, p^{K a} = \log (K a) = - \log (10^{- 4}) P^{k a} = 4 \\ P^{H} = P^{k a} + \log \frac{[C N^{- 1}]}{[H C N]} \\ P^{H} = 4 + 0 [∵ [C N^{-}] = [H C N]] \\ P^{H} = 4 \end{array}$

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