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In a capillary tube experiment, a capillary tube made of glass of radius 0.1m is dipped vertically in a beaker filled with methylene iodine, which rises to height h in the tube. It is observed that the two tangents drawn from liquid glass interfaces (from opposite sides of the capillary) make an angle of $60^{0}$ with one another. Then, h is to (given, surface tension $= 0.05 {Nm}^{- 1}$ , density = 866 ${kg m}^{- 3}$ and ${g = 10 ms}^{- 2})$

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0.1 mm

0.2 mm

0.3 mm

0.4 mm

answer is A.

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Detailed Solution

r = 0.1m $h = \frac{2 T \cos θ}{rdg}$

$θ = \frac{60 °}{2} = 30 °$

$= \frac{2 (5 \times 10^{- 2}) \sqrt{3} / 2}{(0.1) (866) 10}$

$= \frac{(0.1) (0.866)}{866}$

$= 10^{- 4} m$

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