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In a Car lift (hydraulic lift), compressed air exerts a force $F_{1}$ on a small piston of area $A_{1}$ this pressure is transmitted to a second large piston of area $A_{2}$ , mechanical advantage of the device is 5. If the mass of the car to be lifted 1500 kg. The value of $F_{1}$ is (g = 10 m/ $s^{2}$ )

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300 N

3000 N

7500 N

75000 N

answer is B.

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Detailed Solution

$\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}$

$\frac{F_{2}}{F_{1}} = \frac{A_{2}}{A_{1}} \Rightarrow \frac{1500 \times 10}{F_{1}} = 5$

$F_{1} = 3000 N$

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